國二化學酒精含量計算 - 酒精
By Lucy
at 2012-05-27T00:00
at 2012-05-27T00:00
Table of Contents
已知酒精密度為0.8g/ml，水的密度為1g/ml，今有58度之金門高粱酒500ml(不考慮其他香味物質)試問該瓶酒含酒精為ml?為何答案是348ml不知如何計算出來的?
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酒精
All Comments
By Barb Cronin
at 2012-05-30T21:37
at 2012-05-30T21:37
2.58度之金門高粱酒500ml(不考慮其他香味物質)則該瓶酒含酒精為500mlx0.58=290ml
3.貴版大應該是600ml筆誤500ml,計算式為
600mlx0.58=348ml
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