關於近視度數與眼軸長的關係 - 眼鏡

: n/f = (n-1)/R .............(1)
: n/(f+a) ≒ n/f - n*a/f^2 = (n-1)/R - D ............(2)
: a = (f^2)*D/n
: 近視100度的人..D為1.0代入得
: a = (0.02278)^2*1/1.336
: = 0.3884 mm
: 即每近視100度..眼軸長會增加0.3884mm


Among these myopic children, a 0.5mm increase in axial length was
associated with 1D of myopia progression.

(翻譯)
統計顯示，在近視發育過程中，眼軸長每增加0.5mm，其屈光度約增加-1D。


Leslie Hyman, PhD; Jane Gwiazda, PhD; Mohamed Hussein, PhD; Thomas T. Norton,
PhD; Ying Wang, MS; Wendy Marsh-Tootle, OD; Donald Everett, MA;

Relationship of Age, Sex, and Ethnicity With Myopia Progression and Axial
Elongation in the Correction of Myopia Evaluation Trial.

ARCH OPHTHALMOL 2005;123:977-987

我只是想說 生/病理變化大多不是規則的 因此數學模型不適合直接套用在人身上
僅能提供一個變化趨勢的參考

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